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0=12x^2-60x-168
We move all terms to the left:
0-(12x^2-60x-168)=0
We add all the numbers together, and all the variables
-(12x^2-60x-168)=0
We get rid of parentheses
-12x^2+60x+168=0
a = -12; b = 60; c = +168;
Δ = b2-4ac
Δ = 602-4·(-12)·168
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-108}{2*-12}=\frac{-168}{-24} =+7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+108}{2*-12}=\frac{48}{-24} =-2 $
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